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9m^2+3m-56=0
a = 9; b = 3; c = -56;
Δ = b2-4ac
Δ = 32-4·9·(-56)
Δ = 2025
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$m_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$m_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{2025}=45$$m_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(3)-45}{2*9}=\frac{-48}{18} =-2+2/3 $$m_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(3)+45}{2*9}=\frac{42}{18} =2+1/3 $
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